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              Find the area of this regular hexagon which has been decomposed. Round answer to nearest tenth of a sq. unit. | 
            
            
               
                Solution: 
                  A regular hexagon has 6 sides of equal length. 
                The hexagon has been divided into 4 small right triangles and one rectangle. 
                • The area of the 4 right triangles is  ½(5.196)(3)=7.794 sq. units for each triangle 
                • The area of the rectangle is 2(5.196)(6)=62.352 sq. units. 
                Total area = 4(7.794) + 62.352 = 93.528 = 93.5 sq.units 
                   
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              Find the sum of the measures of the interior angles of a pentagon. | 
            
            
               
                Solution: The same strategy that was used with the quadrilateral in the refresher above, will be used here. 
                A pentagon has 5 sides. Draw as many diagonals as possible from the same vertex, to decompose the pentagon into three triangles. 
                A pentagon is now composed of three triangles, each having the sum of their angles = 180º. 
                The sum of the interior angles of a pentagon will be 3 x 180 = 540º.  
                 
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              Find the area of this regular octagon which has been decomposed. | 
            
            
               
                Solution: The regular octagon (with all 8 sides of = length) is divided into 5 rectangles and 4 triangles. 
                • Each of the small Δs has an area of ½(4.4)(4.4) = 9.68 
                  sq. units each. 
                • The square in the center is 6.2 x 6.2 with an area of 38.44 sq. units. 
                  • The 4 remaining rectangles are 4.4 x 6.2 with an area of 27.28 sq. units each.  
                  The total area is  
                4(9.68) + 38.44 + 4(27.28) = 186.28 square units. 
                 
                 
              
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                Lengths have been given to nearest tenth. | 
            
            
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              Find the number of degrees in each interior angle of a regular hexagon. | 
            
            
               
                Solution: In Example 2, we saw how to decompose the pentagon into triangles by drawing diagonals from one vertex. Using this same strategy  in a 6-sided hexagon, produces 4 triangles. 4 x 180 = 720º. 
                The sum of the measures of the angles in a hexagon is 720º. 
                Because this is a "regular" hexagon, we know that all of its angles are of the same measure. 
                If we divide 720 by 6, we find that each interior angle has a measure of 120º.
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              Find the area of this irregular pentagon which has been decomposed. | 
              
            
               
                Solution: This irregular pentagon has been decomposed into a square and a triangle. While not ALL of its sides are the same length, the hash marks tell us that 3 of them are the same length. 
                  • The area of the square is 15 x 15 = 225 sq. units. 
                • The are of the triangle is ½(6)(15) = 45 sq. units. 
                   
                The total area = 225 + 45 = 270 sq. units.  | 
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