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                               |  | If you can solve a linear equation, you can solve a linear  inequality. The process is the same, with one exception ... |  
                             
                               | ... when you multiply (or divide) an inequality by a negative value, you must change the direction of the inequality.
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                             Note: When you finish solving an inequality, you may want to CHECK a couple of values to see if the number line graph is correct. In Example 1, choose 5 from the number line and see if it solves the original inequality. It does (5 - 3 > -2),
                               | Solve and graph the solution set of:    x - 3 > -2 |  
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                                 Solve as you would a linear equation (add 3 to both sides of the statement).
 The solution set for this problem will be all values that satisfy x > 1.
 Graph using  an open circle for x =1 (since x can not equal 1), and an arrow pointing to the right. | x - 3 > -2x > 1
   |  It is important to check back to the "original" inequality, just in case you make an algebraic error.
 You can also check values to the left of 1 on the number line to see that they do NOT solve the original inequality.
  
 
                             
                               | Solve and graph the solution set of:   x + 5 < 8 |  
                               |                                  Solve as you would a linear equation (subtract 5 from both sides of the statement).
 The solution set for this problem will be all values that satisfy x < 3.
 Graph using a closed circle for x = 3 (since x can  equal 3)., and an arrow pointing to the left. | x + 5 < 8x < 3
 
 
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                               | Solve and graph the solution set of:    4x < 24 |  
                               | Again, proceed as you would  when solving a linear equation:Divide both sides by 4.
 Note: The direction of the inequality stays the same since we did NOT divide by a negative value. Graph using an open circle for 6 (since x can not equal 6) and an arrow to the left (since our symbol is less than). | 
 
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                               | Solve and graph the solution set of:   - 5x    25 |  
                               |                                  Divide both sides by -5.
                                  Note: The direction of the inequality was reversed since we divided by a negative value. Graph using a closed circle for -5 (since x can  equal -5) and an arrow to the left (since our final symbol is less than or equal to). | 
 
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                               | Solve and graph the solution set of:   3x + 4 > 13 |  
                               | Proceed as you would  when solving a linear equation:Subtract 4 from both sides.
 Then, divide both sides by 3.
 Note: The direction of the inequality stays the same since we did NOT divide by a negative value. Graph using an open circle for 3 (since x can not equal 3) and an arrow to the right (since our symbol is greater than). | 
 
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                               | Solve and graph the solution set of:   9 - 2x   3 |  
                               | Subtract 9 from both sides.Then, divide both sides by -2.
 Note: The direction of the inequality was reversed since we divided by a negative value. Graph using a closed circle for 3 (since x can  equal 3) and an arrow to the right (since our symbol is greater than or equal to). | 
 
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 For the following problems, alternate forms of expressing the solutions are included. For more information on "alternate notations", see 
                           Notations for Solutions.
 
 
                             
                               | Solve and graph the solution set of:     |  
                               | Proceed as you would  when solving a linear equation with a fraction:
                                 Add 6 to both sides. 
                                 Multiply both sides by   .
                                  Note: The direction of the inequality stays the same since we did NOT multiply by a negative value.
 Graph using a closed circle for 6 (since x can  equal 6) and an arrow to the left (since our symbol is less than or  equal to).
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 Other notations:
   
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                               | Solve and graph the solution set of:   5(x - 3) > 10 |  
                               | Distribute (remove the parentheses).
 Add 15 to both sides.
 
 Divide both sides by 5.
 Note: The direction of the inequality stays the same since we did NOT multiply by a negative value.                                  Graph using a open circle for 5 (since x can  NOT equal 5) and an arrow to the right (since our symbol is greater  than). | Other notations:
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                               | Solve and graph the solution set of:     4(x - 1) > 3(x - 2) |  
                               | Distribute across both sets of  parentheses.
 Subtract 3x from both sides.
 The solution is  easier if you  move the smaller x value.
 
 Add 4 to both sides.
 
                                  Note: The direction of the inequality stays the same since we did NOT multiply or divide by a negative value.                                Graph using an open circle for -2 (since x can not equal -2) and an arrow to the right (since our symbol is greater than). | 
 Other notations:
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